Being an ambidextrous skidder and getting double the number of patches only happens when the chainring/sprocket is an even number like 45, not 46.

huh? 46

*is* and even number. And it has nothing to do with if the chain ring is odd or even numbered. It has to do with how the fraction reduces.

From sheldon brown

Examples:

44/16 simplifies to 11/4, so there would be 4 skid patches.

45/15 simplifies to 3/1 so there would only be 1 skid patch.

42/15 simplifies to 14/5, so there would be 5 skid patches.

43/15 can't be further simplified, so there would be 15 skid patches.

This is based on the assumption that you always skid with the same foot forward.

If you are an ambidextrous skidder, and the simplified ratio has an even numerator or denominator, your number of skid patches will be the same.

If you are an ambidextrous skidder, and both the numerator and denominator are odd, the number of possible skid patches will be doubled.

So 46/16 would reduce to 23/8 which makes 8 skid spots, 16 if you're ambidextrous. And stop telling people that leaders are good.