November 19, 2013 @ 03:21 AM
JEANPAULDAVINCI

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Post: 1088

Join Date: Apr 2012

Location: 916

Ok so I have to find a quadratic function in standard form for a set of points

Here they are
[-1,2],[0,1],[1,-4]

I plug them into the formula

-2=a[1]^2+b[1]+c
a+b+c

1=a[0]^2+b[0]+c
c=1

-4=a[1]^2+b[1]+c= a+b+c

-2=a+b+1 because c=1
-4=a+b+1

subtract 1
-3=a+b
-5=a+b

Now if I were to make either -3 or -5 positive it would also make the and b negative and it would cross out both the a and b. I can only get rid of one.
November 19, 2013 @ 03:29 AM
shnoosetheboose

Post: 809

Join Date: Aug 2012

The first equation is 2 = a - b + c not -2 = a + b + c

The same equations can't have different answers if a and b are constants which is why you're running into trouble at the end.
November 19, 2013 @ 03:30 AM
Mr. Freeze

Post: 5367

Join Date: Feb 2009

I think you need some help on English as well.
November 19, 2013 @ 03:34 AM
AmericanLegend

Post: 2770

Join Date: Jul 2012

Location: USA

if u in highschool 
and have an algebra textbook u can find most of the answers on a website called slader it has em page by pag

taste the glamour

November 19, 2013 @ 03:36 AM
JEANPAULDAVINCI

suspended

Post: 1088

Join Date: Apr 2012

Location: 916

The first equation is 2 = a - b + c not -2 = a + b + c

The same equations can't have different answers if a and b are constants which is why you're running into trouble at the end.


I took your tips and I got

1=a+b
-4=a+b

Lets say [-1]1=a+b 
-1=-a-b
-4=a+b

Would this mean this equation is unsolvable because the and b would both cross out?
November 19, 2013 @ 03:36 AM
SonOfRise

Post: 2970

Join Date: Jan 2013

Location: Earth

if u in highschool 
and have an algebra textbook u can find most of the answers on a website called slader it has em page by pag
Thanks man I'm using this!! 

Zooey Deschanel is waifu

November 19, 2013 @ 03:39 AM
JEANPAULDAVINCI

suspended

Post: 1088

Join Date: Apr 2012

Location: 916

if u in highschool 
and have an algebra textbook u can find most of the answers on a website called slader it has em page by pag
its a given assignment, not in the book 
November 19, 2013 @ 03:44 AM
shnoosetheboose

Post: 809

Join Date: Aug 2012

The first equation is 2 = a - b + c not -2 = a + b + c

The same equations can't have different answers if a and b are constants which is why you're running into trouble at the end.


I took your tips and I got

1=a+b
-4=a+b

Lets say [-1]1=a+b 
-1=-a-b
-4=a+b

Would this mean this equation is unsolvable because the and b would both cross out?
Naw you made another small mistake



that should be right
November 19, 2013 @ 04:01 AM
Kimo 先生

Post: 1950

Join Date: Nov 2010

Location: Hawai'i

this should just be the official help with math thread

http://tinyurl.com/3dln5qa

November 19, 2013 @ 04:09 AM
JEANPAULDAVINCI

suspended

Post: 1088

Join Date: Apr 2012

Location: 916


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